6x^2+24x-12=180

Solution for 6x^2+24x-12=180 equation:

6x^2+24x-12=180

We move all terms to the left:

6x^2+24x-12-(180)=0

We add all the numbers together, and all the variables

6x^2+24x-192=0

a = 6; b = 24; c = -192;
Δ = b2-4ac
Δ = 242-4·6·(-192)
Δ = 5184
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{5184}=72$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-72}{2*6}=\frac{-96}{12}
=-8
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+72}{2*6}=\frac{48}{12}
=4
$